81^2x(1/9)^x+2=729(9^x)^-2

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Solution for 81^2x(1/9)^x+2=729(9^x)^-2 equation: 



81^2x(1/9)^x+2=729(9^x)^-2

We move all terms to the left:

81^2x(1/9)^x+2-(729(9^x)^-2)=0



Domain of the equation: 9)^x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

81^2x(+1/9)^x-(7299^x^-2)+2=0

We get rid of parentheses

81^2x(+1/9)^x-7299^x^+2+2=0

We multiply all the terms by the denominator


81^2x(+1-7299^x^*9)^x+2*9)^x+2*9)^x=0

Wy multiply elements

162x^2+81^2x(+1-7299^x^*9)^x=0

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